SOLUTION: Please help me with the following question: Determine the vertex of y=x^2-8x+22. Thank you!

Question 43880: Please help me with the following question: Determine the vertex of y=x^2-8x+22. Thank you!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Determine the vertex of y=x^2-8x+22. Thank you!
Put the equation in vertex form by completing the square, as follows:
y-22=x^2-8x
y-22+16=x^2-8x+4^2
y-6=(x-4)^2
Vertex is at (4,6).
This is what it looks like.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -24 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -24 is + or - .

The solution is

Here's your graph:

Cheers,
Stan H.
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