SOLUTION: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work
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Question 424068: Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
10x-6y =-11
Find the slope of this line
6y=10x+11
Divide by 6
y=1 2/3 x +1.83
Compare this equation with y=mx+b
slope m = 5/3
The slope of a line perpendicular to the above line will be the negative reciprocal
m1*m2=-1
The slope of the required line will be - 3/5 - 3/5 = -0.60
m= -0.60 ,point (-5,-8)
Find b by plugging the values of m & the point in
y=mx+b
-8=3+b
b=-11
m=- 3/5
The required equation is y=-0.6x -11
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