SOLUTION: Determine the vertex of y=x^2-8x+22
I have D(4,8) is this correct? Thank you.
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Question 42015This question is from textbook
: Determine the vertex of y=x^2-8x+22
I have D(4,8) is this correct? Thank you.
This question is from textbook
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
This is a parabola that opens upward, and the vertex (minimum point) will be at . In this case, vertex is at .
If x = 4, then y = 4^2 - 8*4 +22 = 16 - 32 +22=6.
I get a vertex of (4, 6) . Check it out with the graph:
R^2 at SCC
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