SOLUTION: graph the equation using the slope and the y-intercept. y=5/3x+8

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Question 419197: graph the equation using the slope and the y-intercept.
y=5/3x+8

Found 2 solutions by algebrahouse.com, Edwin McCravy:
Answer by algebrahouse.com(1659)   (Show Source): You can put this solution on YOUR website!
"graph the equation using the slope and the y-intercept.
y = 5/3x + 8"

Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept

In y = 5/3x + 8
slope = 5/3
y-intercept = 8

To graph:
- start by putting a point on 8 on the y-axis, that is the y-intercept
- from there, go up 5 and to the right 3, and put another point (since the slope is 5/3....rise/run}
- draw a line through the two points
www.algebrahouse.com

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
graph the equation using the slope and the y-intercept.



Compare that equation to



and you'll see that m = the slope =  and b=8 and the 
y-intercept is the point (0,b) = (0,8).  We plot the y-intercept,
(0,8):

 

Starting at that y-intercept we take the NUMERATOR of the slope,
which is 5, and draw a VERTICAL line 5 units long UPWARD, since 
the slope is positive (it would be downward if the slope were 
negative), like the green arrow below:



Now from that arrowhead, we turn RIGHT and draw a HORIZONTAL line
equal to the number of units indicated by the DENOMINATOR of the slope, 
that is, 3 units, like the green horizontal line below:



To make the graph, we draw a line through the end of the horizontal
line and the y-intercept (0,8), like this:



That red line is the graph of the equation .

Edwin

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