# SOLUTION: A line passes through (-2,3), (2,5), and (6,k). Find k. I've been finding the slope of the points, using that information to make a point slope {(y-y)=m(x-x)} equation, and turnin

Algebra ->  Algebra  -> Graphs -> SOLUTION: A line passes through (-2,3), (2,5), and (6,k). Find k. I've been finding the slope of the points, using that information to make a point slope {(y-y)=m(x-x)} equation, and turnin      Log On

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 Question 416084: A line passes through (-2,3), (2,5), and (6,k). Find k. I've been finding the slope of the points, using that information to make a point slope {(y-y)=m(x-x)} equation, and turning that into a y=mx+b equation. However, I am not sure how I should go about solving this one.Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website! A line passes through (-2,3), (2,5), and (6,k). Find k. ---- slope = (5-3)/(2--2) = 2/4 = 1/2 --- Equation Form: y = mx = b 5 = (1/2)2 + b b = 4 ---- Equation: y = (1/2)x+4 --- and (6,k). Find k -- y = (1/2)6+4 = 7 k = 7 ======== Cheers, Stan H. =========