Hi

x+3y=6  OR y = (-1/3)x + 2

 



y = (-1/3)x + 2  | slope m = -1/3 and y-intercept is Pt(0,2)

m = -1/3: as y increases/decreases by 1, x increases/decreases by 3 in opposite direction.

 due to the equal sign, the graph is a Line..doesn't call for shading   



 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
  I can't figure out y=mx+b I think I forgot how to solve this. x+3y=6 then I have to put it back and shade one side of the graph.

-----------------------------

If you are shading, you have an inequality.

----

Let's assume you have x+3y < 6.

----

Then y < (-x/3) + 2

-------

Notice: No inequality is graphed directly.

You 1st must graph the boundary, which is 

always an equality.

So, for your problem you should graph 

y EQUALS (-x/3)+2 as a dashed line; dashed

because that boundary is not part of the

solution.

---

Then, since you want y LESS than (-x/3)+2

you should shade the half plane BELOW

the boundary to get:



-------------------

Cheers,

Stan H.

========

 

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