Hi

 



Write an equation of the straight line that is ⊥ to the line y=-5x + 8 

 y = (1/5)x + b  | ⊥ Lines have slopes that are negative reciprocals of one another, that is  -5*(1/5) = -1 

 y = (1/5)x + b  |using order pair Pt(12,0) to solve for

 0 = 12/5 + b

-12/5 = b

 y = (1/5)x -12/5  OR x-5y = 12 in standard form

Note m = 1/5: as y increases/decreases by 1, x increases/decreases by 5  

 

 

 

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