SOLUTION: help!!!!! divide {{{m^2n^3/p^3}}} by {{{mp/n^2}}}

SOLUTION: help!!!!! divide {{{m^2n^3/p^3}}} by {{{mp/n^2}}}

Algebra.Com

Question 39901: help!!!!!
divide by
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE RULE FOR DIVIDING FRACTIONS IS "INVERT THE SECOND TERM (DENOMINATOR) & MULTIPLY THUS
(M~2N~3/P~3)((N~2/MP) OR (M~2N~5)/(MP~4)OR MN~5/P~4
RELATED QUESTIONS
divide m^2 n^3/ p^3 by... (answered by Fombitz)

How do you divide m^2 n^3/p^3 by mp/n^2 m^2=m to the second power etc. I have been... (answered by solver91311)

I am having a hard time with this question, divide m^2 n^3 mp ------- by ------ (answered by ichudov)

If m-p=3 and mp=-1 the what is the value of (m+p)^2? (answered by Alan3354)

Which equation shows that m varies directly with p? M=3/p Mp=1/3 Mp=3... (answered by josmiceli)

m=2(x+n) so far i did this: m=2(x+n) m=2x+2n -2n -2n --------- m-2n=2x ----... (answered by jainenderkapoor)

n^2-2n-3 (answered by checkley79)

I've been working on this problem for 2 hours, and I would like some help. I need to... (answered by ptaylor)

mp^2(m-p)+mp(m-p)-2p^2(m-p) (answered by profemmanuel2q@yahoo.com)