SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
{{{f(x)=-2x^2+2x+1}}}
The x-coordinate of the vertex is ___
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Question 396135: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
The x-coordinate of the vertex is ____.
(Type a simplified fraction.)
The y-coordinate of the vertex is ____.
(Type a simplified fraction.)
The equation of the line of symmetry is x=____.
(Type a simplified fraction.)
The maximum/minimum of f(x) is ____.
(Type a simplified fraction.)
The value, is a minimum or maximum?
Graph.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
The x-coordinate of the vertex of a parabola in the form is given by .
The y-coordinate is then .
The line of symmetry passes through the vertex, so the equation is .
The maximum or minimum is the value of the function at . Whether it is a maximum or minimum depends on whether the parabola opens up or down. If it is concave up (makes a valley rather than a hill), the point is a minimum, otherwise it is a maximum. You can tell which way the parabola opens by the sign on the lead coefficient. if , it is concave down, if , it is concave up, and, of course, if you don't have a parabola at all.
Let's look at your specific problem:
First thing to note is that , so this is a concave down parabola and the vertex is a .
, so the x-coordinate of the vertex is and the equation of the line of is .
The value of the function at , denoted for your problem is
So the y-coordinate of the vertex and the value of is
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