SOLUTION: Can you help? Train A&B traveling in the same direction, train A is traveling at 60 miles per hr and train B is traveling at 70 miles per hr, train A passes a station at 3:25 p.m.

Question 395255: Can you help? Train A&B traveling in the same direction, train A is traveling at 60 miles per hr and train B is traveling at 70 miles per hr, train A passes a station at 3:25 p.m. and train B passes the same station at 3:55 p.m. at what time will train B catch up with train A? Thank you! Shelly
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Train A&B traveling in the same direction, train A is traveling at 60 miles per
hr and train B is traveling at 70 miles per hr, train A passes a station at 3:25
p.m. and train B passes the same station at 3:55 p.m.
at what time will train B catch up with train A?
:
From the given information, we know at 3:25 pm, train B is 30 min behind train A
:
Since it will take .5 hr to reach the station B must be 70*.5 = 35 mi behind A
:
let t = travel time for B to catch A
:
Write a distance equation: dist = speed * time
:
B's travel dist = A's travel dist + 35 mi
70t = 60t + 35
70t - 60t = 35
10t = 35
t =
t = 3.5 hrs for B to catch A
then
3:25 + 3.5 = 6:55 PM B catches A
:
:
Check this by finding the distance each traveled
70 * 3.5 = 245 mi
60 * 3.5 = 210 mi
-----------------
difference: 35 mi
:
:
Did this make sense to you?
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