SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. {{{f(x)=2x^2-12x+8}}}

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Question 394709: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
Found 2 solutions by Alan3354, ewatrrr:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.

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The line if symmetry is x = -b/2a = 12/4
L of S is x = 3
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The minimum is on the L of S at f(3)
f(3) = 2*9 - 12*3 + 8 = -10
Minimum at (3,-10)
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dl the FREE graph software at
http://www.padowan.dk
Use Insert, 2x^2-12x+8

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

the vertex form of a parabola,  where(h,k) is the vertex

  |completing square



  Vertex Pt(3,-10), Line of symmetry is x = 3

Vertex is a minimum value, parabola open upward (a>0) 





 

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