SOLUTION: graph the line through (-2,5) with slope -1. I don't understand this at all, Can anyone help?

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Question 39378This question is from textbook beginning and intermediate algebra
: graph the line through (-2,5) with slope -1. I don't understand this at all, Can anyone help?This question is from textbook beginning and intermediate algebra

Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
when you say "graph". Do you really mean graph, as in plot on graph paper? Or just sketch?

If sketch, then you need to draw some axes and then draw a line like \ that passes through the point (-2,5). As to the exact positioning of this point, it doesn't have to be precise as we are "sketching".

If you need to plot a graph then you need to find the equation of the line. A straight line has generic formula y=mx+c, where m is the gradient (here, -1) and c is the y-intercept (ie where the line crosses the y-axis). We will need to find this value, since we do not know it.

So, we start with y=mx+c which becomes
y=(-1)x+c
y = -x+c

Now we need to figure out the value of c. Well, to do this, we need to know a value for x and y. We do --> (-2,5).

So, y=-x+c
5=-(-2)+c
5=2+c
c = 3

--> equation is y=-x+3

Now we plot the graph, once we have found a few points on the line. Being a straight line we really only need 2 points and join them with a ruler. But one or both of these could have been calculated incorrectly by you, so always do 4 minimum, just in case.

Pick easy (ie small) numbers for x and put these into y=-x+3 to find the equivalent y-value. So,

when x=0, y=?
when x=1, y=?
when x=2, y=?
when x=3, y=?

jon.