SOLUTION: graph {{{f(x)=x^2-6x+8}}}. what are the roots of {{{x^2-6x+8}}}

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Question 39370This question is from textbook algebra 1
: graph f%28x%29=x%5E2-6x%2B8. what are the roots of x%5E2-6x%2B8 This question is from textbook algebra 1

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-6x%2B8
%28x-4%29%28x-2%29
The zeros are 4 and 2
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-6x%2B8+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-6%29%5E2-4%2A1%2A8=4.

Discriminant d=4 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--6%2B-sqrt%28+4+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-6%29%2Bsqrt%28+4+%29%29%2F2%5C1+=+4
x%5B2%5D+=+%28-%28-6%29-sqrt%28+4+%29%29%2F2%5C1+=+2

Quadratic expression 1x%5E2%2B-6x%2B8 can be factored:
1x%5E2%2B-6x%2B8+=+1%28x-4%29%2A%28x-2%29
Again, the answer is: 4, 2. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-6%2Ax%2B8+%29