Hi

graphing first

y = x^2 - 2x + 1   y-intercept (when x=0) = (0,1)

Vertex form found by completing square

y = (x-1)^2  vertex is (1,0)

the vertex form of a parabola,  where(h,k) is the vertex



then shading the 'inner portion' for y>x^2 - 2x + 1 

(parabola itself not included)



 
Solved by pluggable solver: Plot Any Inequality
Graphing function : 

  

  

 

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