SOLUTION: y varies directly with x and has a constant rate of change of 7.
When the value of y is 12, then the value of x would be?
Algebra.Com
Question 388262: y varies directly with x and has a constant rate of change of 7.
When the value of y is 12, then the value of x would be?
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
A change in one quantity with respect to another quantity is called a
.
Any rate of change can be described in terms of slope, or .
A special type of equation that describes a rate of change is a
linear equation in the form of , where is equal to , and is called .
In direct variation we say that varies with or varies directly as .
In the direct variation equation, , is the
of variation.
The constant of variation in a direct variation equation has the as the of the graph.
For example:
is a direct variation because it is in the form of .
The constant of variation of is .
The slope of the linear graph of is . All direct variation graphs pass through the .
So, in your case we have:. The constant of variation it is .
If the value of is , then the value of would be or .
RELATED QUESTIONS
Given: y varies directly with x and has a constant rate of change of 7.
When the value (answered by stanbon)
Y varies directly with X and has a constant rate of change of 6. What is the equation... (answered by ikleyn)
1. Determine the constant of variation for the direct variation given.
R varies directly (answered by stanbon)
The value of y varies directly with x, and y = 18 when x = 12. Find y when x =... (answered by Alan3354)
Id have a question if x varies inversely as y and x=2 when y=8, and i should find x when... (answered by solver91311)
Directions : If y varies directly with x and y=7 when x=56,then find
Question: the... (answered by josgarithmetic)
If y varies directly with x and y = 8 when x = 12, what will be the value of y when x =... (answered by Fombitz)
Find an equation of variation in which y varies directly as x and y=12 when x=1/3. Then... (answered by checkley77)