SOLUTION: A local travel agent can sell up to 1200 travel packages for a concert. The packages will include airfare, hotel, and two types of flights: non-stop or two stop. The non-stop fligh
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Question 375845: A local travel agent can sell up to 1200 travel packages for a concert. The packages will include airfare, hotel, and two types of flights: non-stop or two stop. The non-stop flight carries 150 passengers and the two stop flight carries 100 passengers. The travel agency can use no more than 10 planes. The non-stop package sells for $1200 and the two stop flight sells for $900. Assume that each plane will contain the maximum number of passengers.
a) Write the constraints
b) Find the maximum revenue for the constraints.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A local travel agent can sell up to 1200 travel packages for a concert.
The packages will include airfare, hotel, and two types of flights: non-stop or two stop.
The non-stop flight carries 150 passengers and the two stop flight carries 100 passengers.
The travel agency can use no more than 10 planes.
The non-stop package sells for $1200 and the two stop flight sells for $900.
Assume that each plane will contain the maximum number of passengers.
:
a) Write the constraints
b) Find the maximum revenue for the constraints.
:
Let x = number of 150 passenger planes
Let y = number of 100 passenger planes
:
Number of airplanes:
x + y =< 10
Put in the general (y=) form, to plot on a graph
y =< 10 - x; (purple line)
:
Number of travel packages sold:
150x + 100y =< 1200
100y =< 1200 - 150x
y =< 1200/100 - (150/100)x
y =< 12 - 1.5x; (green line)
:
The graph:
:
Feasibility region is at or below the purple or green lines whichever is lowest
:
The vertices:
x = 8, y = 0
x = 0, y = 10
Solve the two equation system to find the other vertici
150x + 100y = 1200
Simplify, divide by 100
1.5x + y = 12
x + y = 10
----------------subtract, find x
.5x = 2
x = 2/.5
x = 4
:
Find y:
4 + y = 10
y = 6
The 3rd vertici is x = 4, y = 6, 4 ea 150 pass planes, 6 ea 100 pass planes
:
Revenue:
4*150*1200 = $720,000
6*100*900 = $540,000
--------------------
total is $1,260,000 for 4 ea 150 pass planes and 6 ea 100 pass planes
:
Max revenue would be 8 full 150 pass planes at $1,440,000
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