SOLUTION: Please help i have no clue how to do either of these problems. Given f(x)=x^2+3x-2, find f(2) and Given h(x)=4x+8, find 4[h(-3/4)]. Thanks for the help, and please explain how

Question 37359: Please help i have no clue how to do either of these problems.
Given f(x)=x^2+3x-2, find f(2)
and Given h(x)=4x+8, find 4[h(-3/4)].
Thanks for the help, and please explain how to do these problems.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Given f(x) = x^2 + 3x - 2, we merely substitute 2 in for x and compute.
So f(2) = 2^2 + 3(2) - 2 = 4 + 6 - 2 = 8
and
Given h(x) = 4x + 8, we have
4[h(-3/4)] = 4[4(-3/4) + 8] =
4[-3 + 8] =
4[5] =
20
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