Hi,

f(x)=-16x^2+8x+3

f(x)=-16[x^2+(1/2)x -3/16}

f(x)=-16[(x-1/4)^2 - 1/16 -3/16}

f(x)=-16(x-1/4)^2 + 4

x intercepts (y=0)

0 = -16(x-1/4)^2 + 4

-4/-16 = (x-1/4)^2  taking the square root of both sides of the equation

+-2/4 = x - 1/4

1/4 +- 1/2 = x

-1/4 = x

3/4 = x

y intercept (x=0)

y = -16(-1/4)^2 + 4

y = -1 + 4 = 3







 

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