Hi,
the standard point-slope form for an equation of a line y = mx + b where m is the slope and b the y-intercept.
5x+4y-20=0 Solving for 'y'to put the equation into the slope-intercept form
4y = -5x + 20
y = (-5/4)x + 5
slope = (-5/4) and the y intercept is 5. Pt (0,5) a point on the line.
(0,5) The slope tells us the change in y versus the change in x
(4,0) also a point of the line (As y decreases by five,x increases by 4)