SOLUTION: Sue has $3.50 of dimes and nickels. If she has 50 coins, how many of each type of coin does she have?

Algebra.Com
Question 36879: Sue has $3.50 of dimes and nickels. If she has 50 coins, how many of each type of coin does she have?
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
350=10X+5(50-X) OR 350=10X+250-5X OR 100=5X OR X-100/5 OR X=20 DIMES THUS WE HAVE 50-20=30 NICKELS.
PROOF 10*20+5*30=350 OR 200+150=350 OR 350=350

RELATED QUESTIONS

Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by tutor_paul)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by sprolden)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by jim_thompson5910)
56. Number problems. Jill has $3.50 in nickels and dimes. If she has 50 coins, how many... (answered by AnlytcPhil)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by checkley71)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by fractalier)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by fractalier)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by fractalier)
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin... (answered by Nate)