# SOLUTION: Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5)

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 Question 367297: Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5)Answer by nerdybill(7003)   (Show Source): You can put this solution on YOUR website! Perpendicular to the graph of y = 1/3 x + 7; y-intercept (0,5) .56 Because y = 1/3 x + 7 is in "slope-intercept" form: y=mx+b We can see that the slope is: 1/3 . For a line to be perpendicular, the slope of the new line must be the "negative reciprocal": (1/3)m = -1 m = -3 (slope of our new line) . Given that the problem stated that the y-intercept is at (0,5) this means that the 'b' (in the slope intercept form) is 5 . So, our equation is: y = -3x + 5 (this is what they're looking for)