SOLUTION: Can anyone help me with this problem???? I need to see what the graph would look like for f(x)=x^2+2 Please post the graph so that I can see what it looks like....thanks

Algebra ->  Algebra  -> Graphs -> SOLUTION: Can anyone help me with this problem???? I need to see what the graph would look like for f(x)=x^2+2 Please post the graph so that I can see what it looks like....thanks      Log On

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Question 36626: Can anyone help me with this problem????
I need to see what the graph would look like for f(x)=x^2+2
Please post the graph so that I can see what it looks like....thanks
Answer by junior403(76) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=x%5E2+%2B+2
Since this is an exponential function it is a function of a parabola.
We can find our points of the graph by creating a table of values.
We take our exponential expression x%5E2+%2B+2 and substitute values for x.
We should find 7 points: the vertex and 6 corresponding points.
If x = 0 then y = 2 (vertex)
If x = 1 then y = 3
If x = -1 then y = 3
If x = 2 then y = 6
If x = -2 then y = 6
If x = 3 then y = 11
If x = -3 then y = 11
Then we plot the points...
+graph%28+300%2C+200%2C+-8%2C+8%2C+-3%2C+15%2C+x%5E2+%2B+2%29+
This is what the parabola will look like...
I hope this helps
Good Luck!