SOLUTION: Please help me solve this equation: Find equations of the tangents to the curve {{{ x = 3t^2+1 }}}, {{{ y=2t^3+1 }}} that pass through the point (4,3).

SOLUTION: Please help me solve this equation: Find equations of the tangents to the curve {{{ x = 3t^2+1 }}}, {{{ y=2t^3+1 }}} that pass through the point (4,3).

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Question 366017: Please help me solve this equation:
Find equations of the tangents to the curve , that pass through the point (4,3).
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
from (x,y) = (4,3)

we find t = 1

the tangent slope is dy/dx = 6t�/6t = 1 for t = 1

then tangent equation is : y = x - 1 at (4,3), or y = t - 1, x = t

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