Hi, 

***General point-slope from of an equation is 

y = mx + b where m is the slope and b is the value of y where the line crosses the y-axis

Slope -1/2

y = (-1/2)x + b

Using ordered pair (3,-2) to solve for b

-2 = (-1/2)*3 + b

-4/2 + 3/2 = b

-1/2 = b

y = (-1/2)x -1/2

 

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