Hi, 

6y+5x=-18 

solving for y to generate the slope-intercept form y = mx + b

y = -(5/6)x - 3  negative slope, line slants to the left

Line crosses the y axis when y has a value of -3.  Pt(0,-3) the y intercept

slope verifies (-6,2) is a point on the line. (y increasing by 5, x decreasing by 6)

 

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