SOLUTION: Marks: 1
Find the equation passing through the given y-intercept with the given slope.
(0, -6), m = -3
Choose one answer.
A. y = –6x – 3
B. –6x – 3y = 0
C. y = –3x –
Algebra.Com
Question 351025: Marks: 1
Find the equation passing through the given y-intercept with the given slope.
(0, -6), m = -3
Choose one answer.
A. y = –6x – 3
B. –6x – 3y = 0
C. y = –3x – 6
D. –3y = –6
Find the equation passing through the given point with the given slope.
(4, -17), m = -2
Choose one answer.
A. y = -2x – 9
B. y = -2x – 17
C. -2x + 4y = -17
D. 4x – 2y = -9
Marks: 1
Find the slope and the y-intercept for the following equation.
3x + 2y = 6
Choose one answer.
A. m = -3/2, b = -3
B. m = -3/2, b = 3
C. m =3/2, b= -3
D. m =3/2, b=3
Marks: 1
Find the slope and the y-intercept for the following equation.
x - 3y = 9
Choose one answer.
A. m = -1/3, b = -3
B. m = -1/3, b = 3
C. m =1/3, b= -3
D. m =1/3, b=3
Find the x-intercept and the y-intercept for the following equation
5x – 2y = -10
Choose one answer.
A. (0, 5 ); ( -2, 0)
B. (0,-5 ); (2 , 0)
C. (0, -2 ) (5, 0)
D. (0,2 ); (-5, 0)
Find the x-intercept and the y-intercept for the following equation
3x + 7y = -21
Choose one answer.
A. (0, 7 ); ( -3, 0)
B. (0,-7 ); (-3 , 0)
C. (0, -7 ) (3, 0)
D. (0,-3 ); (-7, 0)
Marks: 1
Write an equation for the line passing through the following given points.
(-2, 6), (3,1)
Choose one answer.
A. y = -3x + 4
B. y = x – 4
C. y = -x + 4
D. y = 5x + 4
Marks: 1
Write an equation for the line passing through the following given points.
(-3, 4), (-2,1)
Choose one answer.
A. y = -3x - 5
B. y = 1/3x – 5
C. y = -1/3x + 5
D. y = 3x + 5
Write an equation for the line passing through the following given points.
(0, 2), (1, ¾)
Choose one answer.
A. y = -4/5x + 2
B. y = 4/5x – 2
C. y = -5/4x + 2
D. y = 5/4x -2
Marks: 1
Write an equation for the line parallel to the line 6x + 3y = -8 through the origin.
Choose one answer.
A. y = -2x +0
B. y =2x +0
C. y = -1/2x +0
D. y = 1/2x +0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do them like these:
Given 2 points example.
Find the equation of the line thru the points (2,1) and (3,5)
---------------------
This is a 2 step process. First find the slope of the line thru the points.
slope, m = diffy/diffx
m = (5-1)/(3-2)
m = 4
---------
Now use y = mx + b with either point to find b, the y-intercept.
y = mx + b
5 = 4*3 + b
b = -7
-------
y = mx + b
y = 4x - 7 is the answer.
------------------------
Another approach using determinants:
|x y 1|
|2 1 1| = 0
|3 5 1|
--------
x(1-5) - y(2-3) + 1(10-3) = 0
-4x + y + 7 = 0
y = 4x - 7
---------
For further assistance, or to check your work, email me via the thank you note
or at Moral Loophole@aol.com
----------------------
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
------------------
The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
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