SOLUTION: how do you solve 3a+7 < 16
how do you solve 16 < 3q+4
how do you solve 20-3s > 7s
how do you solve 3x > -9
Algebra.Com
Question 34984: how do you solve 3a+7 < 16
how do you solve 16 < 3q+4
how do you solve 20-3s > 7s
how do you solve 3x > -9
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
I'll do numbers 1 and 3 then you can use these as a guide to solve the others!
1)
Subtract 7 from both sides of the inequality.
Divide both sides by 3.
3)
Add 3s to both sides of the inequality.
Divide both sides by 10.
or
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