SOLUTION: How do I find the equation of the line passing through (2, -3) and (4,0). And then how do I put it into standard form?

Question 345790: How do I find the equation of the line passing through (2, -3) and (4,0). And then how do I put it into standard form?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I find the equation of the line passing through (2, -3) and (4,0). And then how do I put it into standard form?
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slope = m = (-3-0)/(2-4) = -3/-2 = 3/2
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Form: y = mx+b
0 = (3/2)4+b
0 = 6 + b
b = -6
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Equation:
y = (3/2)x-6
===================
Cheers,
Stan H.
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