# SOLUTION: Thank you so much for taking the time to help students like me that are in way over thier heads. I am that is for sure. I really appericate it. Thanks again. First heres the direct

Algebra ->  Algebra  -> Graphs -> SOLUTION: Thank you so much for taking the time to help students like me that are in way over thier heads. I am that is for sure. I really appericate it. Thanks again. First heres the direct      Log On

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 Algebra: Graphs, graphing equations and inequalities Solvers Lessons Answers archive Quiz In Depth

 Question 34493This question is from textbook College algebra : Thank you so much for taking the time to help students like me that are in way over thier heads. I am that is for sure. I really appericate it. Thanks again. First heres the directions; for the points P and Q, find (a)the distance d(P,Q) and (b) the coordinates for the midpoint of the segment PQ. #10 P(-4,3), Q(2,-5) This is what I did... d(P,R)= (under the radical sign) (2-(-4)squared + (-5-3)squared =(2+4) squared + (-5-3)squared =2Squared + 4squared + -5squared -3squared =6squared + -8squared =36+64= 100 under radical sign Heres the midpoint; -4+2/2squared, 3+-5/2squared = -1 and -2/5 I hope you were able to figure out what I did. I am pretty sure I got @ least part of it right. Thanks again. Have a great day. This question is from textbook College algebra Found 2 solutions by Earlsdon, stanbon:Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!It looks like you will have the right distance when you take the square root of 100. For the distance between P(-4, 3) and Q(2, -5): For the coordinates (x, y) of the midpoint of PQ: and and and and The coordinates of the midpoint are: (-1, -1) Answer by stanbon(57219)   (Show Source): You can put this solution on YOUR website!d(P,R)=sqrt[( 2+4)^2 + (-5-3)^2] = sqrt[36+64] = sqrt(100) = 10 Midpoint: x coordinate = (-4+2)/2= -1 y coordinate + (-3-5)/2= -4 Cheers, Stan H.