SOLUTION: Thank you so much for taking the time to help students like me that are in way over thier heads. I am that is for sure. I really appericate it. Thanks again. First heres the direct

Question 34493This question is from textbook College algebra
: Thank you so much for taking the time to help students like me that are in way over thier heads. I am that is for sure. I really appericate it. Thanks again. First heres the directions; for the points P and Q, find (a)the distance d(P,Q) and (b) the coordinates for the midpoint of the segment PQ. #10 P(-4,3), Q(2,-5) This is what I did...
d(P,R)= (under the radical sign) (2-(-4)squared + (-5-3)squared
=(2+4) squared + (-5-3)squared
=2Squared + 4squared + -5squared -3squared
=6squared + -8squared
=36+64= 100 under radical sign
Heres the midpoint; -4+2/2squared, 3+-5/2squared
= -1 and -2/5

I hope you were able to figure out what I did. I am pretty sure I got @ least part of it right. Thanks again. Have a great day.

This question is from textbook College algebra

Found 2 solutions by Earlsdon, stanbon:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
It looks like you will have the right distance when you take the square root of 100.
For the distance between P(-4, 3) and Q(2, -5):

For the coordinates (x, y) of the midpoint of PQ:
and
and
and
and
The coordinates of the midpoint are: (-1, -1)

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
d(P,R)=sqrt[( 2+4)^2 + (-5-3)^2]
= sqrt[36+64]
= sqrt(100) = 10
Midpoint:
x coordinate = (-4+2)/2= -1
y coordinate + (-3-5)/2= -4
Cheers,
Stan H.
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