SOLUTION: How do you find the center, radius, and x and y intercepts of 3x^2-3y^2-6x-12y=0?

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Question 334204: How do you find the center, radius, and x and y intercepts of 3x^2-3y^2-6x-12y=0?
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Complete the square in x and y.






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It's not a circle, it's a hyperbola, so it has no radius.
It's centered at (1,2).
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To find the x-intercepts, set y=0 and solve for x.



(0,0) and (2,0)
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To find the y-intercepts, set x=0 and solve for y.



(0,0) and (0,-4)
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