SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=2x^2-8x+19
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Question 328393: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=2x^2-8x+19
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ ax^2\ +\ bx +\ c)
Is a parabola. The 
-coordinate of the vertex is 
, The 
-coordinate is \ =\ a\left(\frac{-b}{2a}\right)^2\ +\ b\left(\frac{-b}{2a}\right) +\ c)
The axis of symmetry is the line 
The parabola opens upward if 
, and then the vertex is a minimum. The parabola opens downward if 
, and then the vertex is a maximum.
The -intercept is the point ))
, which is to say )
. By symmetry, there is also a point on the parabola at )
If 
, then there are two -intercepts at )
, and )
John
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