SOLUTION: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
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Question 323879: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Let L = liters
0.40L + 10(0.80) = 0.60(L + 10)
The above equation is all you need to find the answer.
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