SOLUTION: Hi,
How would I go about doing this:
Draw a linear graph on the same set of axes and determine the points of intersection from the graphs drawn:
y=x+1
y=-2x-1
y=x-3
Algebra.Com
Question 310002: Hi,
How would I go about doing this:
Draw a linear graph on the same set of axes and determine the points of intersection from the graphs drawn:
y=x+1
y=-2x-1
y=x-3
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Draw a linear graph on the same set of axes and determine the points of intersection from the graphs drawn:
y=x+1
y=-2x-1
y=x-3
----------------
Each eqn will give a graph that's a straight line. Find 2 points and draw a line thru them.
y = x+1
Pick values of x, and find y
x = 0, y = 1 --> (0,1) one point
x = 5, y = 6 --> (5,6) a 2nd point
Plot them, draw a line thru them.
---------------------
Do the same for the other 2 eqns.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Draw a linear graph on the same set of axes and determine the points of intersection from the graphs drawn:
y=x+1
Plot two points and graph:
Let x= 0, then y = 1 giving you point (0,1)
Let x= 2, then y = 3 giving you point (2,3)
Plot and graph:
------------------------------------------
y=-2x-1
Let x= 0, then y = -1 giving you point (0,-1)
Let x = 2, then y = 3 giving you point (2,3)
Plot and graph:
------------------------------------------
y=x-3
Let x = 0, then y = -3 giving you point (0,-3)
Let x = 2, then y = -1 giving you point (2,-1)
Plot and graph:
-------------------------------------------
Plotting them on one set of axis, look for a common point of intersection:
========================
The points of intersection are (-2/3 , 1/3) and (2/3, -2 1/3)
================================================================
Cheers,
Stan H.
=================
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