SOLUTION: 6x+y=44
6x+7y=28
I do it this way correct:
6x+7y(44-6x)=28
6x=308-42x=28
48x+308=28
co efficient is 48
48x+308=28
48x-336
x=7
y=44 -6(7x)
44-42
y = 2
Algebra.Com
Question 301746: 6x+y=44
6x+7y=28
I do it this way correct:
6x+7y(44-6x)=28
6x=308-42x=28
48x+308=28
co efficient is 48
48x+308=28
48x-336
x=7
y=44 -6(7x)
44-42
y = 2
Found 4 solutions by Fombitz, stanbon, unlockmath, JBarnum:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
No, the solution does work.
Test your solution in the original equations.
.
.
Oops!
.
.
.
An easier way may be like this,
Since they both equal set them equal to each other and solve for y.
Take it from there and solve for x.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6x+y=44
6x+7y=28
----
An easier way to do it.
Subtract the 1st Eq. from the 2nd, and solve for "y":
6y = -16
y = -8/3
---------
Substitute for y in the 1st Eq. and solve for "x":
6x + (-8/3) = 44
6x = (132/3)+(8/3)
6x = 140/3
x = 140/18
x = 70/9
=====================
Cheers,
Stan H.
=====================
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's go through each step.
6x+y=44
6x+7y=28
First equation rewritten as:
y=44-6x Plug this into the second equation to get:
6x+7(44-6x)=28
6x+308-42x=28
-36x+308=28
From this point we subtract 308 from both sides to get:
-36x=-280 Divide -36 into both sides to get:
x=280/36 reduced to 70/9
x=70/9
Plug this into either equation:
6(70/9)+7y=28 Do the math:
7y=28-(140/3)
y=-8/3
Check the answer by plugging these answers into either original equation.
Make sense?
RJ
Get a book I wrote on the basics of math at:
www.math-unlock.com
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
easy setup for elimination method
multiply this one by a -1
_____________
Substitution
___________
Elimination
add these equations together
_____
multiply by 1/6
__________________
CHECKING
comes out wrong with either method so either the problem is written incorrectly or the answer is no solutions.
lol looks like im the only tutor who actually checks my answers. 1 guy below checked once but still didnt find that there is no solution to this set of equations.
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