# SOLUTION: Find the equations for the following lines and then graph them using any graphing utility Parallel to 6x - 4y + 12 = 0, and passing through the line x = 3 6 times (3)-4y

Algebra ->  Algebra  -> Graphs -> SOLUTION: Find the equations for the following lines and then graph them using any graphing utility Parallel to 6x - 4y + 12 = 0, and passing through the line x = 3 6 times (3)-4y      Log On

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 Click here to see ALL problems on Graphs Question 298725: Find the equations for the following lines and then graph them using any graphing utility Parallel to 6x - 4y + 12 = 0, and passing through the line x = 3 6 times (3)-4y+12=0 18-4y+12=0 y=30/4 or 7.5 30-4y=0 30=4y 6x-4y+12=0 -4y/-4 = 6x+12/-4 4y=6x+12 y=6/-4x + 12 y=1.5x+12 slope = 6/-4 solution (3, 7.5) So I was able to get this much not sure if it is correct however I am lost when it comes to the graphing and the part of the problem whre it states passing through the line x=3 any help is much appreciated and needed Thank you Eric Answer by richwmiller(9135)   (Show Source): You can put this solution on YOUR website!Please don't yell. We can hear you. We have new batteries in the hearing aids. HELLO I AM LOST ON THIS PROBLEMI I WAS ABLE TO COME UP WITH PART OF THE ANSWER BUT I AM NOW STUCK. I ALSO HAVE NO CLUE HOW TO GRAPH THIS ANY HELP WOULD BE APPRECIATED. All Caps is internet yelling. If it passes through x=3 that means the new line at some time has x=3 the original line has the equation 6x - 4y + 12 = 0 it has a slope of -a/b=-6/-4=3/2 The new line will also have a slope of 3/2 and an x of 3 y=3x/2 is our new line We are pretty sure it will pass through x=3 But how can we be sure? The only lines that won't pass through x=3 are parallel with x=3 x=3 has an undefined slope since y never changes. Our line has a slope of 3/2 so they do intersect. As a further test we can see if the original line passes through x=3 by plugging in 3 for x in the original equation but it is not necessary.