SOLUTION: I need help graphing these functions could I get some help please? y=4x^2 and graph function y=x^2-2

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Question 29731: I need help graphing these functions could I get some help please?

y=4x^2

and graph function y=x^2-2

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
For the first function: , you know (or should know) that this is the equation for a parabola that opens upwards (the coefficient of x^2 is positive) and the x-coordinate of the vertex is given by: .
The a and b come from the standard form for the quadratic equation: , so the vertex of the parabola is: because b = 0, and, in your equation, when x = 0 then y = 0, so the vertex of the parabola is at (0, 0), the origin of the coordinate system.
The x-intercepts can be found by setting y = 0 and solving for x.

and or, there are no x-intercepts which makes sense when you realise that if the parabola opens upwards and the vertex is at the origin, then the parabola never crosses the x-axis.
Here's the graph:

For the second function, you can apply a similar analysis and find that the parabola opens upwards but the vertex is at (0, -2) and the x-intercepts are at x = and x = -
Here's the graph:


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