SOLUTION: Solve for c. a = 1/2 bc2

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 Click here to see ALL problems on Graphs Question 29121: Solve for c. a = 1/2 bc2Answer by sdmmadam@yahoo.com(530)   (Show Source): You can put this solution on YOUR website!Solve for c. a = 1/2 bc2 a = 1/(2bc^2) ----(1) Multiplying by (2bc^2) a(2bc^2) = 1 c^2= [1/2ab] (dividing by 2ab which means a cannot be zero and b cannot be zero) c=+or minus sqrt[1/2ab] c= +[1/sqrt(2ab)] or c= -[1/sqrt(2ab)] Note: sqrt(1/t) = sqrt(1)/sqrt(t) = 1/[(sqrt(t)] Verification: c= +[1/sqrt(2ab)] in (1) RHS = 1/(2bc^2)=1/{2b[1/sqrt(2ab)]^2} = 1/{[2b/2ab]} = 1/[(1/a)] = a =LHS c= -[1/sqrt(2ab)] in (1) gives the same result. Hence our value is right