SOLUTION: write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
Algebra.Com
Question 285404: write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
Found 2 solutions by richwmiller, stanbon:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
slope is -a/b =-7/1=-7
perpendicular slope is 1/7
7=3/7+b
49=3+7b
46=7b
46/7=b
y=x/7+46/7 slope intercept form
7y=x+46
check
7=3/7+46/7
49=3+46
ok
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
------------------------
Find the slope of the given line:
y = -7x+8
slope = -7
--------------------
The slope of any line perpendicular to the
given line is 1/7
-------------------------
Find Equation of line with slope = 1/7 and passing thru (3,7)
---
7 = (1/7)3 + b
49/7 = 3/7 + b
b = 46/7
-------------------
Equation:
y = (1/7)x+(46/7)
===========================
Cheers,
Stan H.
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