SOLUTION: through (7,2) parallel to 3x-y=8 written in slope intercept form and standard form?

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Question 282218: through (7,2) parallel to 3x-y=8
written in slope intercept form and standard form?

Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
First, get the main equation into slope-intercept form: y = mx + b
.
3x -y = 8
-y = -3x +8
y = 3x - 8
.
Second, you recall that any line with slope = 3 will be parallel to this line.
Your problem is define such a line that goes through the point (7,2).
Well, plug x=7 into the equation and then adjust 'b' to make y=2.
.
y = 3x -b
2 = 3(7) -b
2 = 21 -b
-19 = -b
b = 19
.
so,
y = 3x -19 will be parallel and will go through the point.
.
Check by graphing the two equations. y=3x-8 is red; y=3x-19 is green.

.
Rechecking the question, this equation needs to be shown in slope-intercept and in standard form.
y = 3x-19 :: slope-intercept form
.
Standard form is: Ax + By = C
.
subtract 3x from both sides
-3x + y = -19
.
multiply both sides by -1
.
3x -y = 19 :: standard form
.
Done

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