SOLUTION: write an equationfor the line that is perpendicular to the given line and that passes through the given point
y=x-3;(4,6) and
find the slope of a line perpendicular to the grap
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Question 278185: write an equationfor the line that is perpendicular to the given line and that passes through the given point
y=x-3;(4,6) and
find the slope of a line perpendicular to the graph of each equation y=-3x
Found 2 solutions by subbbu, stanbon:
Answer by subbbu(3) (Show Source): You can put this solution on YOUR website!
passes through the given point
y=x-3;(4,6) and
slope of any line perpendicular to a given line of slope m =-1/m since their slopes product must be equal to -1.
y =x-3.
slope m =1.
slope a kine perpenducolr to this line =-1/1 =-1.
(4,6)
y-y1=m(x-x1)
y-6= -1(x-4)
y-6== -x+4
y+x-10 =0.
find the slope of a line perpendicular to the graph of each equation y=-3x
slopof y =-3x m =-3.
as said above slope of a line perpendiculr to y =-63x is -1/-3 =1/3.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write an equation for the line that is perpendicular to the given line and that passes through the given point
y=x-3;(4,6)
Given line slope is 1; slope of the perpendicular line must be -1
----
Equation Form: y = mx + b
6 = -4 + b
b = 10
Equation:
y = -x + 10
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and
find the slope of a line perpendicular to the graph of each equation y=-3x
The Given line has slope = -3
Any line perpendicular to it has slope = 1/3
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Cheers,
Stan H.
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