SOLUTION: Here is the question on my quiz sheet- Find the slopes of the lines that are (a) parallel and (b) perpendicular to the line through the pair of points (-3,-3) and (2, 2) x1

Algebra ->  Algebra  -> Graphs -> SOLUTION: Here is the question on my quiz sheet- Find the slopes of the lines that are (a) parallel and (b) perpendicular to the line through the pair of points (-3,-3) and (2, 2) x1      Log On

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Question 27107: Here is the question on my quiz sheet-
Find the slopes of the lines that are (a) parallel and (b) perpendicular to the line through the pair of points
(-3,-3) and (2, 2)
x1 y1 x2 y2 (so you see what i did)
The possible answers are -1;1, 0;0, 1;-1, -3/2; 2/3 I chose -1;1
I got -1 by taking 2-3 (y2-y1)=-1 and 2-3 (x2-x1)=-1 but I do not know how to find perpendicular or if I am even doing this problem correctly to begin with. I am having a very hard time period with graphing. Thank you so much for any help that you can give me so that I understand (or try to) what exactly I am supposed to be doing. If I can understand how this problem works then I should be able to figure out how the other one is figured out on my quiz. thanks again...Angi
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
You were actually on the right track, very good.
The one mistake you did when figuring out the slope;
The fromula;
m=%28y2-y1%29%2F%28x2-x1%29
When you subtract the y2-y1 and x2-x1,
you will actutally add;
%282-%28-3%29%29%2F%282-%28-3%29%29
youforgot to change the sign of the -3 to +3, that would make you adding;
%282%2B3%29%2F%282%2B3%29
5%2F5=1
So the slope of a parallel line would be 1, and then a perpendicular line would be -1;
You were doing great, at least you remembered the formula, you made the mistake SO MANY students make, watch those signs!!!
Good Luck on your test
=)