SOLUTION: graph the solutions of each linear inequality 4x-y<3 and 3x+4y<12

Question 263131: graph the solutions of each linear inequality 4x-y<3 and 3x+4y<12
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
4x-y<3
step 1 - subtract 4x to get
-y<-4x+3
step 2 - divide by -1 ; don't for get the negative rule about switching the inequality when multiply or divide by - number. We get
y >4x - 3
here is the graph

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and 3x+4y<12
step 1 - subtract 3x to get
4y<-3x + 12
step 2 - divide by 4 to get
y < (-3/4)x + 3
here is the graph

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