SOLUTION: x^2+y^2+8x+2y+13=0 Find the center and radius. If someone could explain the steps that would be great!!

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Question 262418: x^2+y^2+8x+2y+13=0 Find the center and radius. If someone could explain the steps that would be great!!
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Here is the original equation
(i) x%5E2%2By%5E2%2B8x%2B2y%2B13=0
step 1 - rearrange the terms so that x's are grouped and y's are grouped together.
(ii) x%5E2+%2B+8x+%2B+_____+%2B+y%5E2+%2B+2y+%2B+_____+=+-13+%2B+_____+%2B+_____
the blanks are waiting for certain numbers
step 2 - take 1/2 of the middle terms and square it
(1/2)*8 = 4 -> 4^2 = 16
(1/2)*2 = 1 -> 1^2 = 1
so, we get
(iii) x%5E2+%2B+8x+%2B+4%5E2+%2B+y%5E2+%2B+2y+%2B+1%5E2+=+-13+%2B+4%5E2+%2B+1%5E2
notice that the blanks were filled in with the squared numbers.
step 3 - rewrite the x any y trinomial as a binomial squared. Also, simplify the right side to get
(iv) %28x%2B4%29%5E2+%2B+%28y+%2B+1%29%5E2+=+4
notice that the constant is 1/2 the middle term.
we have everything we need to find center and radius.
center = (h,k) = (-4,-1)
radius = 2