# SOLUTION: Graph x^2 -2x +y^2=8 y^2=-x^2 -2x+8 y=-x^2 -2x+8 (this line + or - the Square root of the entire equation) I dont know if I am entering it wrong into the calc., but it is suppos

Algebra ->  Algebra  -> Graphs -> SOLUTION: Graph x^2 -2x +y^2=8 y^2=-x^2 -2x+8 y=-x^2 -2x+8 (this line + or - the Square root of the entire equation) I dont know if I am entering it wrong into the calc., but it is suppos      Log On

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 Algebra: Graphs, graphing equations and inequalities Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Graphs Question 261817: Graph x^2 -2x +y^2=8 y^2=-x^2 -2x+8 y=-x^2 -2x+8 (this line + or - the Square root of the entire equation) I dont know if I am entering it wrong into the calc., but it is suppose to be a graph of a circle.Answer by solver91311(16868)   (Show Source): You can put this solution on YOUR website! Complete the square on : Divide the coefficient on the first degree term by 2 and square the result. -2 divided by 2 is -1. -1 squared is 1. Add the result to both sides of the equation: Factor the perfect square trinomial in : Re-write as : A circle centered at and with radius has an equation: So find the point and draw a circle with radius 3 centered there. John