SOLUTION: what is the equation of a line that contains points (4,2)and (0,-1)?

Question 255265: what is the equation of a line that contains points (4,2)and (0,-1)?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
what is the equation of a line that contains points (4,2)and (0,-1)?
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1st find the slope, m
m = diffy/diffx = (-1-2)/0-4)
m = 3/4
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Then use y = mx + b with either point to find b:
2 = (3/4)*4 + b
b = -1
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y = mx + b
y = (3/4)x - 1 slope-intercept form
3x - 4y = 4 standard form

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