SOLUTION: find the domain of the equation
g(x)=9/10-9x
***9 is over 10-9x. didnt want to confuse you.
Algebra.Com
Question 254669: find the domain of the equation
g(x)=9/10-9x
***9 is over 10-9x. didnt want to confuse you.
Found 3 solutions by drk, stanbon, palanisamy:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
The question was
--
To find domain, we ask two questions:
(1) is the variable in a square root?
If yes, the set that stuff >=0.
If no, then question 2
(2) is the variable in the denominator?
If yes set the denominator not = 0 and solve
If no, then say "all reals".
--
Our variable is in denominator so
10-9x not = 0
-9x not = -10
x not = 10/9.
The domain is all reals except 10/9.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the domain of the equation
g(x)=9/(10-9x)
---
The denominator cannot be zero.
10-9x = 0
9x = 10
x = 10/9
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Domain: "All Real Numbers except x = 10/9}.
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Cheers,
Stan H.
Answer by palanisamy(496) (Show Source): You can put this solution on YOUR website!
Given,
g(x) = 9/(10-9x)
We can assign any value to x such that the denominator is not zero
If the denominator is zero, 10-9x = 0
-9x = -10
x = -10/(-9)
x = 10/9
Therefore we can assign any value to x other than 10/9
The domain is all real values other than 10/9
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