SOLUTION: the vertex of 2x^2 + 8x + 1 is at what point

Question 249751: the vertex of
2x^2 + 8x + 1 is at what point
Found 2 solutions by jsmallt9, tutorcecilia:
Answer by jsmallt9(3759) (Show Source): You can put this solution on YOUR website!
I assume the equation is
When the equation of a parabola is in the form , then the x coordinate of the vertex is . In your equation, the "a" is 2 and the "b" is 8, so the x coordinate of the vertex is

Now that we know the x coordinate of the vertex we can use the equation to figure out its y coordinate:

So the coordinates of the vertex are: (2, -7)
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
2x^2 + 8x + 1 is at what point
[use the formula for finding the x-value of the vertex]
[plug-in the appropriate values from the equation]
x=-2
.
y=2x^2 + 8x + 1
y=2(-2)^2 + 8(-2) + 1 [plug-in the x-value (-2) and solve for the y-value]
y=8-16+1
y=-7
.
So, the vertex point is (-2, -7)
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