SOLUTION: Write the equation of the line L satisfying the given geometric conditions. the first one is - L has y-intercept (0, -3) and is parallel to the line with equation y=2/3x + 1.

Algebra ->  Graphs -> SOLUTION: Write the equation of the line L satisfying the given geometric conditions. the first one is - L has y-intercept (0, -3) and is parallel to the line with equation y=2/3x + 1.       Log On


   

Question 24900: Write the equation of the line L satisfying the given geometric conditions.
the first one is - L has y-intercept (0, -3) and is parallel to the line with equation y=2/3x + 1.
the second one is - L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The first line has the SAME slope as y = 2/3x + 1, which is m = 2/3. If its y intercept is -3, then the equation must be
y+=+%282%2F3%29x+-+3

The second line must be perpendicular to 2x - 3y = 6. You have to solve for y in order to find the slope:
2x-3y = 6
-3y = -2x + 6

Divide both sides by -3:
y+=%28-2x%29%2F%28-3%29+%2B+6%2F%28-3%29
y+=+%282%2F3%29x+-2, so the slope of this line is 2%2F3.

The slope of a line PERPENDICULAR to this line is the NEGATIVE RECIPROCAL of 2%2F3, which is -3%2F2. If the line has a y intercept of 2, then the equation of the line is
y+=+%28-3%2F2%29x%2B+2.

R^2 at SCC