SOLUTION: I haven't taken algebra in 4 years I just need help refreshing. The problem says to find the center and the radius of the graph of the circle. 9x^2+9y^2-6y-17=0

Question 24796: I haven't taken algebra in 4 years I just need help refreshing. The problem says to find the center and the radius of the graph of the circle.
9x^2+9y^2-6y-17=0
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
First, you need to put your equation into the standard form for a circle with centre at (h, k) and radius r.
To accomplish this, you will need to "complete the square" in the y-terms. The x-term is already squared so it does not need to be changed. Here are the steps:
1) Add 17 to both sides of the equation.
2) Divide through by 9.
3) Complete the square in the y-terms by adding the square of half the y-coefficient (that's ) to both sides of the equation.
4) Simplify and factor the y-group.
5) Rewrite the x-term as
6) Compare this with the standard form:
7)
You can see that the centre: (h, k) is (0, 1/3) and the radius, r, is
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